Data di iscrizione: 15 mag 2022

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Fotoğraf: Category:Windows-only software Category:Windows multimedia software Category:Windows-only software freewareQ: "or" operator in bash I have a few questions related to bash "or" operator. For example in the bash script: #!/bin/bash echo if [ -e /tmp/blablabla.bla] then echo "/tmp/blablabla.bla exists" else echo "/tmp/blablabla.bla doesn't exist" fi How it actually works? Is it like first condition is executed and all the checks after it (including the else part) are ignored? Does it depend on order of evaluation? Does the same behavior apply to all "or" operators? In that particular case I would like to know the result of the first check, but if it's possible to run it in this way it's ok with me. A: From man bash: or: The conditional operator. If the first argument is non-zero, the second is taken to be true; otherwise, the second is taken to be false. That means that it is the second part of the conditional statement that is tested, regardless of the position of the if statement. For example: $ if [ -e /tmp/blablabla.bla] > then > echo "/tmp/blablabla.bla exists" > else > echo "/tmp/blablabla.bla doesn't exist" > fi /tmp/blablabla.bla exists A: From the bash man page: if [ testspec1 ]; then [ conditionalcommand ] && [ conditionalcommand2 ]; else [ conditionalcommand ]; fi The exit status of [ is the exit status of conditionalcommand. If [ returns a zero exit status, then the conditional command is executed. Otherwise, the conditional command is not executed. This is an example of the order of precedence. The short answer is that the first test is tested and the remainder are ignored. In the example, the else is not tested until after the first test returns a zero exit status. That answer





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